I’m Stock Right At The Middle Of Solving An Exponential Equation, Could You Please Help Me Out?

-4 + 2 (3)^2x-3 = 10
So here’s how I started:
-4 + 6^2x-3 = 10
I added +4 to both sides,
6^2x-3 = 14
Then I took the common log from both sides, and I got Log(6^2x-3) =log(14)
and so then I simplified and I got, (2x-3) Log(6) = log (14) But here I’m stock! How do I solve this?
Thanks!

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This entry was posted on Tuesday, March 16th, 2010 at 9:27 am and is filed under Stock. You can follow any responses to this entry through the RSS 2.0 feed. You can leave a response, or trackback from your own site.

3 Responses to “I’m Stock Right At The Middle Of Solving An Exponential Equation, Could You Please Help Me Out?”

  1. (2x-3) * log 6 = log 14
    2x-3 = log(14)/log(6) (use calci… if you are not allowed to use calci .. u have to use log tables).. i calculated and the answer is
    2x-3 = 1.47
    2x = 3.47
    x = 1.735

  2. Well before you even did anything you’re off to a bad start. You can’t multiply the base of the exponential by 2. You can’t simplify that in anyway. Try again, good luck.

  3. Start by adding 4 to both sides. Then divide both sides by 2. Now take the log of both sides.

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